Pregunta
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You can afford a \( \$ 800 \) per month mortgage payment. You've found a 30 year loan at \( 8 \% \) interest. a) How big of a loan can you afford? Round your answer to the nearest dollar. b) How much total money will you pay the loan company? Round your answer to the nearest dollar. c) How much of that money is interest? Round your answer to the nearest dollar. Question Help: Dost to forum Suhmit Ousction

Ask by Davison Rose. in the United States
Feb 19,2025

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You can afford a loan of approximately \$108,937. Over 30 years, you'll pay a total of \$288,000, of which \$179,063 will be interest.

Solución

We start with the standard formula for the monthly payment on a fixed‐rate mortgage:   Payment = P · [r(1 + r)ⁿ] / [(1 + r)ⁿ – 1], where   P = principal (the amount of the loan),   r = monthly interest rate, and   n = number of monthly payments. In this problem:   Monthly Payment = $800,   Annual interest rate = 8%, so the monthly interest rate is    r = 0.08/12 ≈ 0.00666667,   n = 30 years × 12 months/year = 360. It is often simpler to solve for the loan principal by rearranging the formula. Solving for P we have   P = Payment · { [ (1 + r)ⁿ – 1 ] / [ r(1 + r)ⁿ ] }. An equivalent (and often used) formula is   P = Payment · [1 – (1 + r)^(–n)] / r. We now plug in the numbers. Step 1. Compute (1 + r)ⁿ:   (1 + 0.00666667)³⁶⁰. A quick way to compute this is by using logarithms:   ln(1.00666667) ≈ 0.00662252,   so ln[(1.00666667)³⁶⁰] ≈ 360 × 0.00662252 ≈ 2.38411,   and (1.00666667)³⁶⁰ ≈ e^(2.38411) ≈ 10.846. Step 2. Now compute P using the alternate formula:   P = 800 · [1 – (1/10.846)] / 0.00666667. Find (1 + r)^(–n):   (1 + r)^(–n) = 1/10.846 ≈ 0.09219. Then:   1 – (1 + r)^(–n) = 1 – 0.09219 = 0.90781. So the principal is:   P ≈ 800 · 0.90781 / 0.00666667    = 800 × (0.90781 ÷ 0.00666667). Calculate the division:   0.90781 ÷ 0.00666667 ≈ 136.1715. Then:   P ≈ 800 × 136.1715 ≈ 108,937. Thus, (a) the maximum loan amount you can afford is about $108,937. Step 3. To find (b) the total amount paid over the life of the loan, multiply the monthly payment by the number of payments:   Total paid = 800 × 360 = 288,000 dollars. Step 4. To find (c) the total interest paid, subtract the principal from the total amount paid:   Interest = 288,000 – 108,937 = 179,063 dollars. Rounded to the nearest dollar, our answers are: a) Loan amount: $108,937 b) Total paid over 30 years: $288,000 c) Total interest paid: $179,063

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To figure out how big of a loan you can afford, we can use the mortgage payment formula, which is \( M = P \frac{r(1 + r)^n}{(1 + r)^n - 1} \). Here, \( M \) is your monthly payment, \( P \) is the loan amount, \( r \) is the monthly interest rate, and \( n \) is the number of payments. With an interest rate of \( 8\% \) annually, your monthly rate is \( \frac{0.08}{12} = 0.00667 \). For a 30-year term, \( n = 30 \times 12 = 360 \). Solving for \( P \), your monthly payment of \( 800 \) results in a total loan of approximately \( \$ 99,000 \). After calculating the total amount paid over the loan's life, you multiply your monthly payment \( 800 \) by the total number of payments \( 360 \), resulting in \( 800 \times 360 = \$ 288,000 \). So, that's the total amount you'll pay back to the loan company over 30 years. To find out how much of that is interest, you subtract the principal amount (the loan amount) from the total payments. Therefore, \( 288,000 - 99,000 = \$ 189,000 \) will go towards interest, resulting in a significant figure over the life of your mortgage. Just think of all the little coffee runs you could have made with that cash instead!

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