$$ 6 a+11 a b-10 b $$ quadratic trinomials

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To analyze the expression $$ 6a + 11ab - 10b $$ as a quadratic trinomial, we can rearrange it in standard form. A quadratic trinomial typically has the form $$ Ax^2 + Bx + C $$.

In this case, we can treat $$ a $$ as the variable and $$ b $$ as a constant. The expression can be rewritten as:

$$
11ab + 6a - 10b
$$

Now, let's identify the coefficients:

- The coefficient of $$ a^2 $$ (which is $$ A $$) is $$ 0 $$ since there is no $$ a^2 $$ term.
- The coefficient of $$ a $$ (which is $$ B $$) is $$ 11b + 6 $$.
- The constant term (which is $$ C $$) is $$ -10b $$.

Thus, the expression can be viewed as:

$$
0a^2 + (11b + 6)a - 10b
$$

This is a quadratic trinomial in terms of $$ a $$.

If you need further analysis or specific calculations (like factoring or finding roots), please let me know!
The expression $$ 6a + 11ab - 10b $$ is a quadratic trinomial in terms of $$ a $$.

quadratic
trinomials

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