\( 1 \leftarrow \quad \begin{array}{l}\text { Express in terms of } i . \\ \sqrt{-252}\end{array} \)

To express \( \sqrt{-252} \) in terms of \( i \), we first recognize that \( \sqrt{-1} = i \). Therefore, we can rewrite \( \sqrt{-252} \) as follows: \[ \sqrt{-252} = \sqrt{252} \cdot \sqrt{-1} = \sqrt{252} \cdot i \] Next, we simplify \( \sqrt{252} \). The prime factorization of 252 is \( 2^2 \cdot 3^2 \cdot 7 \). Thus, we can simplify: \[ \sqrt{252} = \sqrt{(2^2)(3^2)(7)} = 2 \cdot 3 \cdot \sqrt{7} = 6\sqrt{7} \] Combining this with the earlier step, we get: \[ \sqrt{-252} = 6\sqrt{7} \cdot i \] So, in final form, we have: \[ \sqrt{-252} = 6\sqrt{7}i \]