Use repeated subtraction on your calculator to compute the division problem, where a remainder is possible. \( 131+5 \) A. 27 B. 26 R 1 C. 26 R 4 D. 26

To perform repeated subtraction for the division problem \( 131 + 5 \), which simplifies to \( 136 \), you would subtract the divisor (5) from the dividend (136) until what's left is less than the divisor. Starting from 136, subtracting 5 repeatedly gives you 131, then 126, 121, ..., down to 1. You can subtract 5 a total of 27 times (5 x 27 = 135) before reaching 1, which is less than 5. So, the answer is A. 27. In the context of division, it's also helpful to know that the number of times you can subtract gives you the quotient, and any remaining amount gives you the remainder. In this case, you'd be left with a remainder of 1 after 27 subtractions. Fun fact: this method used to be common before calculators made division easy!