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Quiz Active TIMEREMAINII When finding the margin of error for the mean of a normally distributed population from a sample, what is the critical probability, assuming a confidence level of \( 86 \% \) ? 0.14 0.8 0.95 0.95

Ask by Marshall Stephens. in the United States
Feb 25,2025

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The critical probability is 0.14.

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To find the critical probability for a confidence level of \( 86\% \), we need to understand the relationship between the confidence level and the critical probability. 1. **Confidence Level**: The confidence level represents the proportion of the distribution that we expect to capture the true population parameter. In this case, the confidence level is \( 86\% \). 2. **Critical Probability**: The critical probability is the area in the tails of the normal distribution that is not included in the confidence level. It can be calculated as: \[ \text{Critical Probability} = 1 - \text{Confidence Level} \] 3. **Calculation**: \[ \text{Critical Probability} = 1 - 0.86 = 0.14 \] Thus, the critical probability for a confidence level of \( 86\% \) is \( 0.14 \). The correct answer is \( 0.14 \).

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To determine the critical probability for an 86% confidence level, you'll want to divide the remaining area in the tails of the normal distribution. That's 1 - 0.86 = 0.14. Since the confidence level represents the area under the curve in the middle, we divide the remaining area by 2, giving us \( 0.14/2 = 0.07 \). Therefore, you'd use \( 0.07 \) for the critical region in each tail. Now, if you're using a Z-table to find the critical value, you would look for the Z-score that corresponds to a cumulative probability of \( 0.93 \) (0.86 + 0.07). This will give you the critical value needed for calculating the margin of error. Be sure not to confuse your probabilities and to keep track of where your confidence level stands!

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