Pregunta
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1. On a single toss of one die, find the probability of obtaining a) The number 4 b) an odd number c) an even number d) a number less than 4 e) a number greater than 4 f) an odd or an even number 2. In a junior school class of 28 pupils, 7 are in both a sports team and the school band. There are 16 pupils involved in sports teams and 10 in the school band. Find the probability that a pupil chosen at random. a) is only in the school band b) is in either a sports team or the school band c) is in neither a sports team nor the school band 3. An integer is selected randomly from a set of integers \( \{1,2,3,4,5,6,7,8,9,10,11,12\} \). Find the probability that the integer is a) an even number or is divisible by 3 b) an even number and is not divisible by 3 c) not an even number and is not divisibleby 3 . 4. For the sample space \( S \), it is given that \[ \begin{array}{c} P(A)=0.5 \\ P(A \cup B)=0.6 \\ P(A \cap B)=0.2 \end{array} \] Find: a) \( P(B) \) b) \( P\left(A^{\prime} \cap B\right) \) c) \( P\left(A \cap B^{\prime}\right) \) d) \( P\left(A^{\prime} \cap B^{\prime}\right) \) 5. \( \quad C \) and \( D \) are two events where \( P(C)=0.1, P(D)=0.2 \) and \( P(C \cup D)=0.3 \). a) Determine whether \( C \) and \( D \) are two mutually exclusive events. b) Find \( P\left(C^{\prime}\right) \) and \( P\left(C^{\prime} \cap D^{\prime}\right) \) 6. The events \( A, B, C \) and \( D \) are mutually exclusive with \( P(A)=P(B)=0.3 \) and \( P(C)= \) \( P(D)=0.1 \). If \( E \) and \( F \) are events defined by \( E=A \cup D \) and \( F=B \cup C \), find a) \( P(E \cup F) \) b) \( P(E \cap F) \)

Ask by Turnbull Whittaker. in Malaysia
Mar 18,2025

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1. **Probability of Outcomes from a Single Die Toss:** - **a)** \( P(4) = \frac{1}{6} \) - **b)** \( P(\text{odd}) = \frac{1}{2} \) - **c)** \( P(\text{even}) = \frac{1}{2} \) - **d)** \( P(<4) = \frac{1}{2} \) - **e)** \( P(>4) = \frac{1}{3} \) - **f)** \( P(\text{odd or even}) = 1 \) 2. **Probability in a Junior School Class:** - **a)** \( P(B \text{ only}) = \frac{3}{28} \) - **b)** \( P(T \cup B) = \frac{19}{28} \) - **c)** \( P(\text{neither}) = \frac{9}{28} \) 3. **Probability from a Set of Integers:** - **a)** \( P(\text{even or divisible by 3}) = \frac{2}{3} \) - **b)** \( P(\text{even and not divisible by 3}) = \frac{1}{3} \) - **c)** \( P(\text{not even and not divisible by 3}) = \frac{1}{3} \) 4. **Given Probabilities:** - **a)** \( P(B) = 0.3 \) - **b)** \( P(A^{\prime} \cap B) = 0.1 \) - **c)** \( P(A \cap B^{\prime}) = 0.3 \) - **d)** \( P(A^{\prime} \cap B^{\prime}) = 0.4 \) 5. **Events \( C \) and \( D \):** - **a)** \( C \) and \( D \) are mutually exclusive. - **b)** \( P(C^{\prime}) = 0.9 \), \( P(C^{\prime} \cap D^{\prime}) = 0.7 \) 6. **Mutually Exclusive Events \( A, B, C, D \):** - **a)** \( P(E \cup F) = 0.6 \) - **b)** \( P(E \cap F) = 0 \)

Solución

Let's solve each part of the problem step by step. ### 1. Probability of outcomes from a single die toss A standard die has 6 faces numbered from 1 to 6. **a)** Probability of obtaining the number 4: - There is 1 favorable outcome (4). - Total outcomes = 6. \[ P(4) = \frac{1}{6} \] **b)** Probability of obtaining an odd number: - Odd numbers on a die: 1, 3, 5 (3 favorable outcomes). \[ P(\text{odd}) = \frac{3}{6} = \frac{1}{2} \] **c)** Probability of obtaining an even number: - Even numbers on a die: 2, 4, 6 (3 favorable outcomes). \[ P(\text{even}) = \frac{3}{6} = \frac{1}{2} \] **d)** Probability of obtaining a number less than 4: - Numbers less than 4: 1, 2, 3 (3 favorable outcomes). \[ P(<4) = \frac{3}{6} = \frac{1}{2} \] **e)** Probability of obtaining a number greater than 4: - Numbers greater than 4: 5, 6 (2 favorable outcomes). \[ P(>4) = \frac{2}{6} = \frac{1}{3} \] **f)** Probability of obtaining an odd or an even number: - Since all outcomes are either odd or even, the probability is: \[ P(\text{odd or even}) = 1 \] ### 2. Probability in a junior school class Let: - \( n(S) = 28 \) (total pupils) - \( n(T) = 16 \) (pupils in sports teams) - \( n(B) = 10 \) (pupils in the school band) - \( n(T \cap B) = 7 \) (pupils in both) **a)** Probability that a pupil is only in the school band: \[ n(B \text{ only}) = n(B) - n(T \cap B) = 10 - 7 = 3 \] \[ P(B \text{ only}) = \frac{3}{28} \] **b)** Probability that a pupil is in either a sports team or the school band: \[ n(T \cup B) = n(T) + n(B) - n(T \cap B) = 16 + 10 - 7 = 19 \] \[ P(T \cup B) = \frac{19}{28} \] **c)** Probability that a pupil is in neither a sports team nor the school band: \[ n(\text{neither}) = n(S) - n(T \cup B) = 28 - 19 = 9 \] \[ P(\text{neither}) = \frac{9}{28} \] ### 3. Probability from a set of integers The set is \( \{1,2,3,4,5,6,7,8,9,10,11,12\} \) (12 integers). **a)** Probability that the integer is an even number or is divisible by 3: - Even numbers: 2, 4, 6, 8, 10, 12 (6 outcomes). - Divisible by 3: 3, 6, 9, 12 (4 outcomes). - Common (even and divisible by 3): 6, 12 (2 outcomes). \[ P(\text{even or divisible by 3}) = \frac{6 + 4 - 2}{12} = \frac{8}{12} = \frac{2}{3} \] **b)** Probability that the integer is an even number and is not divisible by 3: - Even numbers not divisible by 3: 2, 4, 8, 10 (4 outcomes). \[ P(\text{even and not divisible by 3}) = \frac{4}{12} = \frac{1}{3} \] **c)** Probability that the integer is not an even number and is not divisible by 3: - Odd numbers: 1, 3, 5, 7, 9, 11 (6 outcomes). - Not divisible by 3: 1, 5, 7, 11 (4 outcomes). \[ P(\text{not even and not divisible by 3}) = \frac{4}{12} = \frac{1}{3} \] ### 4. Given probabilities Given: \[ P(A) = 0.5, \quad P(A \cup B) = 0.6, \quad P(A \cap B) = 0.2 \] **a)** Find \( P(B) \): \[ P(B) = P(A \cup B) - P(A) + P(A \cap B) = 0.6 - 0.5 + 0.2 = 0.3 \] **b)** Find \( P(A^{\prime} \cap B) \): \[ P(A^{\prime} \cap B) = P(B) - P(A \cap B) = 0.3 - 0.2 = 0.1 \] **c)** Find \( P(A \cap B^{\prime}) \): \[ P(A \cap B^{\prime}) = P(A) - P(A \cap B) = 0.5 - 0.2 = 0.3 \] **d)** Find \( P(A^{\prime} \cap B^{\prime}) \): \[ P(A^{\prime} \cap B^{\prime}) = 1 - P(A \cup B) = 1 - 0.6 = 0.4 \] ### 5. Events \( C \) and \( D \) Given: \[ P(C) = 0.1, \quad P(D) = 0.2, \quad P(C \cup D) = 0.3 \] **a)** Determine if \( C \) and \( D \) are mutually exclusive: - If they were mutually exclusive, \( P(C \cup D) = P(C) + P(D) \). \[ P(C) + P(D) = 0.1 + 0.2 = 0.3 \quad \text{(equal to } P(C \cup D)\text{)} \] Thus, \( C \) and \( D \) are mutually exclusive. **b)** Find \( P(C^{\prime}) \) and \( P(C^{\prime} \cap D^{\prime}) \): \[ P(C^{\prime}) = 1 - P(C) = 1 - 0.1 = 0.9 \] \[ P(C^{\prime}

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Sure! Let’s dive into the exhilarating world of probability with a dash of historical context and exciting real-world applications. Did you know that the foundations of probability date back to the 16th century? Mathematicians like Gerolamo Cardano started exploring games of chance and gambling. They laid the groundwork for what would eventually evolve into the formal study of probability. This rich history informs not only mathematics but also plays a crucial role in various fields such as economics, game theory, and statistics! In the real world, probabilities guide decisions every day! For instance, weather forecasting uses probability to predict the chance of rain, which helps you decide whether to carry an umbrella. Similarly, in healthcare, probabilities are crucial in determining the likelihood of diseases based on symptoms. Understanding probability not only helps in making informed choices but also in evaluating risks associated with those choices!

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