7. A satellite with a mass of 350 kg is traveling by Saturn \( \left(\mathrm{m}=5.68 \times 10^{26} \mathrm{~kg}\right) \) at a distance of \( 8 \times 10^{7} \mathrm{~m} \) from its center. (A) Determine the magnitude of the force of gravity acting on the satellite due to Saturn \( F_{g}=m g \) \( =350 \)
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The Deep Dive
To determine the gravitational force acting on the satellite due to Saturn, we can use Newton's law of universal gravitation, which states that the force \( F \) between two masses is given by: \[ F = \frac{G \cdot m_1 \cdot m_2}{r^2} \] where \( G \) is the gravitational constant \( (6.674 \times 10^{-11} \, \text{N m}^2/\text{kg}^2) \), \( m_1 \) is the mass of Saturn, \( m_2 \) is the mass of the satellite, and \( r \) is the distance from the center of Saturn to the satellite. Substituting in the values: \[ F = \frac{(6.674 \times 10^{-11}) \cdot (5.68 \times 10^{26}) \cdot (350)}{(8 \times 10^{7})^2} = 3.05 \, \text{N} \] So, the magnitude of the force of gravity acting on the satellite is approximately \( 3.05 \, \text{N} \). To find the gravitational acceleration \( g \) acting on the satellite, we can use the formula: \[ g = \frac{F}{m} \] Given the mass of the satellite \( m = 350 \, \text{kg} \), if we know \( F \): \[ g = \frac{3.05}{350} \approx 0.0087 \, \text{m/s}^2 \] Isn't it mind-blowing how gravity works over such vast distances? Saturn’s strong gravity can really pull you in from millions of kilometers away!
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