Pregunta
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7. A satellite with a mass of 350 kg is traveling by Saturn \( \left(\mathrm{m}=5.68 \times 10^{26} \mathrm{~kg}\right) \) at a distance of \( 8 \times 10^{7} \mathrm{~m} \) from its center. (A) Determine the magnitude of the force of gravity acting on the satellite due to Saturn \( F_{g}=m g \) \( =350 \)

Ask by Gough Logan. in the United States
Jan 09,2025

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The gravitational force acting on the satellite due to Saturn is approximately \( 2.08 \, \text{N} \).

Solución

To determine the magnitude of the gravitational force acting on the satellite due to Saturn, we can use Newton's law of universal gravitation, which is given by the formula: \[ F_g = \frac{G \cdot m_1 \cdot m_2}{r^2} \] where: - \( F_g \) is the gravitational force, - \( G \) is the gravitational constant, approximately \( 6.674 \times 10^{-11} \, \text{m}^3/\text{kg} \cdot \text{s}^2 \), - \( m_1 \) is the mass of Saturn (\( 5.68 \times 10^{26} \, \text{kg} \)), - \( m_2 \) is the mass of the satellite (\( 350 \, \text{kg} \)), - \( r \) is the distance from the center of Saturn to the satellite (\( 8 \times 10^{7} \, \text{m} \)). Now, we can substitute the known values into the formula to calculate the gravitational force \( F_g \). Let's perform the calculation step by step: 1. Substitute the values into the formula: \[ F_g = \frac{(6.674 \times 10^{-11}) \cdot (5.68 \times 10^{26}) \cdot (350)}{(8 \times 10^{7})^2} \] 2. Calculate \( (8 \times 10^{7})^2 \): \[ (8 \times 10^{7})^2 = 64 \times 10^{14} = 6.4 \times 10^{15} \] 3. Now substitute this back into the equation: \[ F_g = \frac{(6.674 \times 10^{-11}) \cdot (5.68 \times 10^{26}) \cdot (350)}{6.4 \times 10^{15}} \] 4. Calculate the numerator: \[ (6.674 \times 10^{-11}) \cdot (5.68 \times 10^{26}) \cdot (350) = 1.33 \times 10^{16} \] 5. Now divide the numerator by the denominator: \[ F_g = \frac{1.33 \times 10^{16}}{6.4 \times 10^{15}} \approx 2.08 \, \text{N} \] Thus, the magnitude of the gravitational force acting on the satellite due to Saturn is approximately \( 2.08 \, \text{N} \).

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The Deep Dive

To determine the gravitational force acting on the satellite due to Saturn, we can use Newton's law of universal gravitation, which states that the force \( F \) between two masses is given by: \[ F = \frac{G \cdot m_1 \cdot m_2}{r^2} \] where \( G \) is the gravitational constant \( (6.674 \times 10^{-11} \, \text{N m}^2/\text{kg}^2) \), \( m_1 \) is the mass of Saturn, \( m_2 \) is the mass of the satellite, and \( r \) is the distance from the center of Saturn to the satellite. Substituting in the values: \[ F = \frac{(6.674 \times 10^{-11}) \cdot (5.68 \times 10^{26}) \cdot (350)}{(8 \times 10^{7})^2} = 3.05 \, \text{N} \] So, the magnitude of the force of gravity acting on the satellite is approximately \( 3.05 \, \text{N} \). To find the gravitational acceleration \( g \) acting on the satellite, we can use the formula: \[ g = \frac{F}{m} \] Given the mass of the satellite \( m = 350 \, \text{kg} \), if we know \( F \): \[ g = \frac{3.05}{350} \approx 0.0087 \, \text{m/s}^2 \] Isn't it mind-blowing how gravity works over such vast distances? Saturn’s strong gravity can really pull you in from millions of kilometers away!

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