If \( f(x) \) is defined as follows, find (a) \( f(-3) \), (b) \( f(0) \), and \( (c) f(3) \). \( f(x)=\left\{\begin{array}{ll}x^{2} & \text { if } x<0 \\ -2 & \text { if } x=0 \\ 2 x+2 & \text { if } x>0\end{array}\right. \) \( \begin{array}{l}\text { (a) } f(-3)=9 \text { (Simplify your answer.) } \\ \text { (b) } f(0)-\square \text { (Simplify your answer.) }\end{array} \)

To find the values of \( f(-3) \), \( f(0) \), and \( f(3) \) based on the piecewise function: (a) For \( f(-3) \): Since \( -3 < 0 \), we use the first piece of the function: \[ f(-3) = (-3)^2 = 9. \] (b) For \( f(0) \): Since \( x = 0 \), we use the second piece of the function: \[ f(0) = -2. \] (c) For \( f(3) \): Since \( 3 > 0 \), we use the third piece of the function: \[ f(3) = 2(3) + 2 = 6 + 2 = 8. \] So the answers are: (a) \( f(-3) = 9 \) (b) \( f(0) = -2 \) (c) \( f(3) = 8 \)