How many volleyball games are played in a 5 -team league if each team plays all other teams twice?

In a 5-team league where each team plays every other team twice, you'll first determine how many unique matchups there are. The formula for finding the number of matches between teams is \( \frac{n(n-1)}{2} \), where \( n \) is the number of teams. Here, \( n = 5 \), so \( \frac{5(5-1)}{2} = \frac{5 \times 4}{2} = 10 \). Since each matchup occurs twice, simply multiply by 2. Thus, there will be \( 10 \times 2 = 20 \) games played in total. So there you have it, 20 thrilling volleyball games where each team gets to showcase their skills against all the others twice! It's a real treat for fans and players alike!