A sample of oak has a density of 807 kilograms per cubic meter. The sample is in the shape of a cube, where each edge has a length of 0.90 meters. To the nearest whole number, what is the mass, in kilograms, of this sample? (A) 588 (B) 726 (C) 897 (D) 1,107

To find the mass of the oak sample, first calculate the volume of the cube. The volume \( V \) of a cube can be found using the formula: \[ V = \text{edge length}^3 \] Substituting the edge length: \[ V = 0.90 \, \text{m} \times 0.90 \, \text{m} \times 0.90 \, \text{m} = 0.729 \, \text{m}^3 \] Next, use the density to find the mass \( m \) using the formula: \[ m = \text{density} \times V \] Substituting the given density and the calculated volume: \[ m = 807 \, \text{kg/m}^3 \times 0.729 \, \text{m}^3 \approx 589.863 \, \text{kg} \] Rounding this to the nearest whole number gives you: **(A) 588**