Pregunta
Question 4
The gradient of the line joining the two points
and
is
.
a) Write down the gradient of the line which is parallel to
.
b) Write down the gradient of the line which is perpendicular to
.
c) Find the equation of the line parallel to
and passing through the point
.
Give your final answer in standard form
.
d) Find the equation of the line perpendicular to
and passing through the point
. Give your final answer in standard form
.
The gradient of the line joining the two points
a) Write down the gradient of the line which is parallel to
b) Write down the gradient of the line which is perpendicular to
c) Find the equation of the line parallel to
Give your final answer in standard form
d) Find the equation of the line perpendicular to
Ask by Harris Harmon. in Dominica
Mar 31,2025
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
Responder
(a) The gradient of the line parallel to
is
.
(b) The gradient of the line perpendicular to
is
.
© The equation of the line parallel to
passing through
is
.
(d) The equation of the line perpendicular to
passing through
is
.
Solución
(a) The gradient of the line parallel to
is the same as the gradient of
, so it is
(b) The gradient of the line perpendicular to
is the negative reciprocal of
, so it is
© To find the equation of the line parallel to
that passes through
, we start with the point-slope form:
Multiplying both sides by 4 to eliminate the fraction gives:
Rearrange the equation into standard form
:
(d) To find the equation of the line perpendicular to
that passes through
, we use the slope
in the point-slope form:
Multiply both sides by 3:
Rearrange into standard form:
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Beyond the Answer
The gradient of the line parallel to
will be the same, so it is also
. For a line to be perpendicular, its gradient must be the negative reciprocal, which would be
. So, we have our gradients: parallel line gradient
and perpendicular line gradient
.
To find the equation of the line parallel to
and passing through the point
, we can use the point-slope form of the line equation:
which becomes:
Simplifying leads to:
Now, rearranging in standard form
:
For the equation of the line perpendicular to
passing through the point
, use the same point-slope form:
This simplifies to:
Changing
to a fraction gives:
Rearranging gives:
And there you have it! The equations are:
- Parallel line:
- Perpendicular line:

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