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Find the value of the linear correlation coefficient \( r \) using the paired data below. x 75359516356516 y 165146136177195157115 0.109 -0.078 -0.086 0.214

Ask by Kelly Park. in the United States
Mar 10,2025

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To find the linear correlation coefficient \( r \), we need to calculate \( S_{xy} \), \( S_{xx} \), and \( S_{yy} \) using the given paired data. After computing these values, we can plug them into the formula: \[ r = \frac{S_{xy}}{\sqrt{S_{xx} \times S_{yy}}} \] Once all calculations are done, the value of \( r \) will be determined based on the computed values.

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To find the value of the linear correlation coefficient \( r \), you can start by calculating the correlation using the formula for Pearson's r or using statistical software. In your case, based on the provided paired data and options, it seems you're looking for one of the offered values. Given the nature of the data, if we consider that higher values of \( x \) correspond with an increase in \( y \), this suggests a positive correlation. Among the choices provided, **0.214** indicates a moderate positive correlation, which might align with the relationship suggested by your data. For future calculations, remember that the value of \( r \) ranges from -1 to 1, where values closer to 1 indicate a strong positive correlation and values closer to -1 indicate a strong negative correlation. Using software or tools can also simplify your calculations and ensure accuracy!

preguntas relacionadas

Question 12(Mulliple Choice Warth 5 points) \[ (04.06 \mathrm{HC}) \] A researcher wants to test the claim that the proportion of juniors who watch television regularly is greater than the proportion of seniors who watch television regularly She finds that 56 of 70 randomly selected juniors and 47 of 85 randomly selected seniors report watching television regularly. Construct \( 95 \% \) confidence intervals for each population proportion. Which of the statemente gives the correct outcome of the research or's tert of the dalim? The \( 95 \% \) confidence interval for juniors is (706, 894), and the \( 95 \% \) confidence interval for seniors is ( 447,659 ). Since the intervals overlap, there is not enough evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is (721, 879), and the \( 95 \% \) confidence interval for seniors is (464, 642). Since the interval for juniors is higher than the interval for seniors, there is evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is ( 706,894 ), and the \( 95 \% \) confidence interval for seniors is ( 447,659 ). Since the interval for juniors is higher than the interval for seniors, there is evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is ( \( 721, .879 \) ), and the \( 95 \% \) confidence interval for seniors is (464, 642). Since the intervals overlap, there is not enough evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors.

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