c. \( \sqrt[3]{-\frac{125}{216}} \cdot(-0,8)-6^{-1}+\sqrt{0,3} \cdot \sqrt{1,2} \)

Let’s break this down step by step for clarity and fun! First, we can simplify \( \sqrt[3]{-\frac{125}{216}} \). The cube root of \(-\frac{125}{216}\) is \(-\frac{5}{6}\) since \( -5^3 = -125 \) and \( 6^3 = 216\). Now, for the second part, we multiply that by \(-0.8\): \(-\frac{5}{6} \cdot -0.8 = \frac{5 \cdot 0.8}{6} = \frac{4}{6} = \frac{2}{3}\). Now, let's tackle \( -6^{-1} \) which equals \(-\frac{1}{6}\). Next is \( \sqrt{0.3} \cdot \sqrt{1.2} \). We can combine these under a single square root: \(\sqrt{0.3 \cdot 1.2} = \sqrt{0.36} = 0.6\). Putting it all together: \(\frac{2}{3} - \frac{1}{6} + 0.6\). Now, converting \(\frac{2}{3}\) to sixths gives \(\frac{4}{6}\), so: \(\frac{4}{6} - \frac{1}{6} + \frac{6}{10}\). Now, this is where we might run into some math fun! To add \(\frac{4}{6}\) and \(-\frac{1}{6}\), we get \(\frac{3}{6} = \frac{1}{2}\). Now, let's convert \(0.6\) to its fractional form, which is \(\frac{3}{5}\). To find a common denominator for \(\frac{1}{2}\) and \(\frac{3}{5}\): The least common multiple of 2 and 5 is 10. Converting gives us \(\frac{5}{10}\) and \(\frac{6}{10}\). Now combine: \(\frac{5}{10} + \frac{6}{10} = \frac{11}{10}\). So, the final answer is \(\frac{11}{10}\) or 1.1! 🎉