3. Five couples want to have their pictures taken. In how many ways can they arrange themselves in a row if a. couples must stay together? b. they may stand anywhere? 4. There are 12 people in a dinner gathering. In how many ways can the host (one of the 12) arrange his guests around a dining table if a. they can sit on any of the chairs? b. 3 people insist on sitting beside each other? c. 2 people refuse to sit beside each other? 5. A teacher drew a number line on the board and named some points on it. The teacher then asked the class to list all the rays in the figure. A I student answered 30 rays in all and the teacher said it was correct. How many points were named in the figure?
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Extra Insights
Think of arranging couples as unique entities; when they stay together, you can treat each couple like a single "block." For five couples, you'd arrange 5 blocks in a line (5!) and then multiply that by the arrangements within each couple (2 for each couple), leading to 5! × 2^5. Meanwhile, without restrictions, use 10! since each person is separate, resulting in 10! arrangements! For the dinner gathering, arranging guests around a circular table is a bit tricky! With 12 guests, one can "fix" one guest and arrange the remaining 11, giving you 11! ways. If 3 insist on sitting together, treat them as one block and arrange the 10 blocks (9 people + 1 block of 3), yielding 10! × 3! arrangements. Finally, if 2 refuse to sit together, you can use the total arrangements minus the cases where they sit together, leading to 12! - arrangements where they are treated as a block.
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