IQ scores are normally distributed with mean 100 and standard deviation 15 . Ten percent of IQ scores are above what value? 119 75 125 81
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To find the cutoff value above which 10% of IQ scores fall, we need to look at the z-score that corresponds to the 90th percentile in a standard normal distribution. The z-score for 90% is approximately 1.281. Applying the z-score formula: Value = μ + z * σ Value = 100 + 1.281 * 15 ≈ 119.215. So, approximately 10% of IQ scores are above 119. If you're ever in a situation where you forget how to use the z-table or calculate certain percentiles, remember to rely on statistical software or apps! They can quickly provide you with z-scores and even perform more complex calculations without the fuss of formulas. Plus, be careful with rounding; using too many decimals can lead to small errors that may alter your results significantly!
