\( 1 \leftarrow \quad \) Solve. \( \quad \sqrt[3]{x-7}-4=0 \)

To solve the equation \( \sqrt[3]{x-7} - 4 = 0 \), start by isolating the cube root term. Add 4 to both sides: \( \sqrt[3]{x-7} = 4 \). Next, cube both sides to eliminate the cube root: \( x - 7 = 4^3 \). Since \( 4^3 = 64 \), we have \( x - 7 = 64 \). Finally, add 7 to both sides to find \( x \): \( x = 64 + 7 = 71 \). Thus, the solution is \( x = 71 \).