Summarize the pertinent information obtained by applying the graphing strategy and sketch the graph of \( f(x)=\frac{x+3}{x-3} \) Find the domain of \( f(x) \). Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The domain is all real \( x \), except \( x= \) (Type an integer or a decimal. Use a comma to separate answers as needed) B. The domain is all real \( x \). Find the x-intercepts of \( f(x) \). Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The x-intercept(s) is/are at \( x= \) (Type an integer or a decimal Use a comma to separate answers as needed.) B. There are no \( x \)-intercepts. Find the \( y \)-intercepts of \( f(x) \). Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The y-intercept(s) is/are at \( y= \) ? (Type an integer or a decimal. Use a comma to separate answers as needed.)

To summarize the pertinent information about the function \( f(x)=\frac{x+3}{x-3} \), we start by identifying its domain. The function is defined for all real numbers except where the denominator is zero, which happens when \( x=3 \). Therefore, the domain is all real \( x \), except \( x=3 \). Now, when it comes to finding the x-intercepts, we set \( f(x) = 0 \). This leads us to the equation \( \frac{x+3}{x-3} = 0 \), which occurs when the numerator equals zero, giving the intercept at \( x = -3 \). Thus, the x-intercept is at \( x = -3 \). Next, we look for the y-intercept by finding \( f(0) \): \[ f(0) = \frac{0+3}{0-3} = -1 \] Thus, the y-intercept is at \( y = -1 \). So in conclusion: - The domain is all real \( x \), except \( x=3 \). - The x-intercept(s) is at \( x=-3 \). - The y-intercept(s) is at \( y=-1 \). Sketching the graph involves plotting these intercepts, noting the vertical asymptote at \( x=3 \), and observing the behavior as \( x \) approaches this line from both sides. It will help visualize the function's behavior for better understanding!