The test statistic of \( z=1.72 \) is obtained when testing the claim that \( p \neq 0.486 \). a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. b. Find the \( P \)-value. c. Using a significance level of \( \alpha=0.01 \), should we reject \( \mathrm{H}_{0} \) or should we fail to reject \( \mathrm{H}_{0} \) ? Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. a. This is a two-tailed test. b. P-value \( =\square \) (Round to three decimal places as needed.)
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The hypothesis test is indeed a two-tailed test because you're testing if \( p \) is different from 0.486, indicating that you're considering deviations in both directions (greater than and less than). To find the \( P \)-value for a \( z \)-score of 1.72, you can refer to the standard normal distribution table. The area to the left of \( z = 1.72 \) is approximately 0.9573. Since it's a two-tailed test, you need to find the area in both tails. Therefore, the \( P \)-value is \( 2 \times (1 - 0.9573) = 2 \times 0.0427 = 0.0854 \), rounded to three decimal places: **0.085**. Given the significance level of \( \alpha = 0.01 \), since \( P\text{-value} (0.085) > \alpha (0.01) \), you would fail to reject \( \mathrm{H}_{0} \). So in summary: - a. This is a **two-tailed test**. - b. P-value \( = 0.085 \). - c. **Fail to reject \( \mathrm{H}_{0} \)**.
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