s default My Courses CRN 40938 Chapter 5 HW - Continuous Random Variables Current score: +Å Category: Homework 0/50 points 1) 2 3 4 5 6 7 8 9 10 Current learning objective: Continuous Probability Functions Question 1 Practice similar questions Score: 0 of 5 points Consider the continuous probability density function defined by \( f(x)=5 \) on \( 0 \leq x \leq \frac{1}{5} \). Then, \( P(0.18

Ask by Lee Nunez. in the United States

Feb 04,2025

To find the probability \( P(0.18 < X < 0.2) \) using the given probability density function \( f(x) = 5 \) for \( 0 \leq x \leq \frac{1}{5} \), we need to consider the interval where \( f(x) \) is defined. Since \( 0.18 \) and \( 0.2 \) are outside the bounds of \( 0 \leq x \leq 0.2 \), the probability over this interval would be calculated as \( P(X) = \int_{0.18}^{0.2} f(x) \, dx \). However, since the function is defined only up to \( \frac{1}{5} = 0.2 \), the probability calculated actually equals zero because the function doesn’t exist in the specified range. If you want to calculate probabilities for this distribution correctly, remember that continuous probability functions only apply within their defined intervals. Always ensure your upper and lower bounds fit within these limits before proceeding with your calculations!