4 Comven each division problem into another, equivalent division problem that you can solve in your head \begin{tabular}{|l|l|l}\hline a. \( \frac{16}{0.4}=-\square \) & b. \( \frac{7}{0.007}=\square \) & c. \( \frac{99}{0.11}=- \) \\ \hline\end{tabular}

To convert each division problem into an equivalent one that can be solved mentally, we can eliminate the decimals by multiplying both the numerator and the denominator by the same power of 10. Let's solve each problem step by step. ### a. \( \frac{16}{0.4} = -\square \) 1. **Convert the division**: Multiply both the numerator and the denominator by 10 to eliminate the decimal. \[ \frac{16 \times 10}{0.4 \times 10} = \frac{160}{4} \] 2. **Perform the division**: \[ \frac{160}{4} = 40 \] Thus, \( \frac{16}{0.4} = -40 \). ### b. \( \frac{7}{0.007} = \square \) 1. **Convert the division**: Multiply both the numerator and the denominator by 1000 to eliminate the decimal. \[ \frac{7 \times 1000}{0.007 \times 1000} = \frac{7000}{7} \] 2. **Perform the division**: \[ \frac{7000}{7} = 1000 \] Thus, \( \frac{7}{0.007} = 1000 \). ### c. \( \frac{99}{0.11} = -\square \) 1. **Convert the division**: Multiply both the numerator and the denominator by 100 to eliminate the decimal. \[ \frac{99 \times 100}{0.11 \times 100} = \frac{9900}{11} \] 2. **Perform the division**: \[ \frac{9900}{11} = 900 \] Thus, \( \frac{99}{0.11} = -900 \). ### Summary of Results - a. \( \frac{16}{0.4} = -40 \) - b. \( \frac{7}{0.007} = 1000 \) - c. \( \frac{99}{0.11} = -900 \)