Part 4 of 4 (d) The ratio \( \frac{a-b}{a-b}=\square \), whereas the ratio \( \frac{a-b}{b-a}=\square \) provided that \( a \neq b \).

Let \( a \) and \( b \) be numbers with \( a \neq b \). 1. First, consider the ratio \[ \frac{a-b}{a-b}. \] Since the numerator and the denominator are the same (and not zero because \( a \neq b \)), we have \[ \frac{a-b}{a-b}=1. \] 2. Next, consider the ratio \[ \frac{a-b}{b-a}. \] Notice that \[ b-a = -(a-b). \] Substituting this into the ratio, we obtain \[ \frac{a-b}{b-a} = \frac{a-b}{-(a-b)} = -\frac{a-b}{a-b} = -1. \] Thus, the completed statements are: - \(\frac{a-b}{a-b}=1\), - \(\frac{a-b}{b-a}=-1\).