\begin{tabular}{|l|l} Solve. \\ \( 36 s^{2}-25=0 \)\end{tabular} \( \begin{array}{l}\text { The solution set is }\{\square\} . \\ \text { (Use a comma to } \\ \text { separate answers.) }\end{array} \)

1. Start with the equation: \[ 36s^2 - 25 = 0 \] 2. Isolate the term with \( s^2 \) by adding 25 to both sides: \[ 36s^2 = 25 \] 3. Divide both sides by 36: \[ s^2 = \frac{25}{36} \] 4. Take the square root of both sides, remembering to consider both the positive and negative roots: \[ s = \pm \sqrt{\frac{25}{36}} = \pm \frac{5}{6} \] The solution set is \( \left\{-\frac{5}{6}, \frac{5}{6}\right\} \).