Pregunta
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The following data set is the age of customers at the ice cream shop: \[ 18,52,42,36,5,31,29,22 \] Find the mean.

Ask by Rogers Perkins. in the United States
Mar 09,2025

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The mean age is 29.375.

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Bonus Knowledge

To find the mean, you need to add all the ages together and then divide by the number of customers. So, adding the ages: \(18 + 52 + 42 + 36 + 5 + 31 + 29 + 22 = 235\). Now, divide this sum by the total number of customers, which is 8: \(235 \div 8 = 29.375\). Therefore, the mean age of customers at the ice cream shop is approximately 29.38 years. Now that's a scoop of knowledge! Just like enjoying different flavors of ice cream, calculating the mean comes in handy in many areas of life, like analyzing survey data or financial stats. It's a sweet way to understand a group better!

preguntas relacionadas

Question 12(Mulliple Choice Warth 5 points) \[ (04.06 \mathrm{HC}) \] A researcher wants to test the claim that the proportion of juniors who watch television regularly is greater than the proportion of seniors who watch television regularly She finds that 56 of 70 randomly selected juniors and 47 of 85 randomly selected seniors report watching television regularly. Construct \( 95 \% \) confidence intervals for each population proportion. Which of the statemente gives the correct outcome of the research or's tert of the dalim? The \( 95 \% \) confidence interval for juniors is (706, 894), and the \( 95 \% \) confidence interval for seniors is ( 447,659 ). Since the intervals overlap, there is not enough evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is (721, 879), and the \( 95 \% \) confidence interval for seniors is (464, 642). Since the interval for juniors is higher than the interval for seniors, there is evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is ( 706,894 ), and the \( 95 \% \) confidence interval for seniors is ( 447,659 ). Since the interval for juniors is higher than the interval for seniors, there is evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is ( \( 721, .879 \) ), and the \( 95 \% \) confidence interval for seniors is (464, 642). Since the intervals overlap, there is not enough evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors.

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