Practice 11. A hyprid car with an initial velocity of \( 10.0 \mathrm{~m} / \mathrm{s}[E] \) accelerates at \( 3.0 \mathrm{~m} / \mathrm{s}^{2} \) [E]. How long will it take the car to acquire a final velocity of \( 25.0 \mathrm{~m} / \mathrm{s} \) [E]?

To find the time it takes for the hybrid car to acquire a final velocity of \( 25.0 \mathrm{~m/s} \) [E], we can use the formula for acceleration: \[ a = \frac{\Delta v}{\Delta t} \] Where: - \( a \) is the acceleration (\( 3.0 \mathrm{~m/s}^2 \)), - \( \Delta v \) is the change in velocity (\( v_f - v_i \)), - \( \Delta t \) is the time. First, calculate the change in velocity: \[ \Delta v = 25.0 \mathrm{~m/s} - 10.0 \mathrm{~m/s} = 15.0 \mathrm{~m/s} \] Now, plug in the values into the acceleration formula: \[ 3.0 \mathrm{~m/s}^2 = \frac{15.0 \mathrm{~m/s}}{\Delta t} \] Rearranging the formula to find \( \Delta t \): \[ \Delta t = \frac{15.0 \mathrm{~m/s}}{3.0 \mathrm{~m/s}^2} = 5.0 \mathrm{~s} \] So, it will take the hybrid car **5.0 seconds** to reach a final velocity of \( 25.0 \mathrm{~m/s} \) [E]. Feel free to let me know if you have any more questions!