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Summarize the pertinent information obtained by applying the graphing strategy and sketch the graph of \( f(x)=1+3 e^{-0.2 x} \) Find the intervals where \( f(x) \) is concave upward or downward. Select the correct choice below and fill in the answer box(es) to complete your choice. (Type your answer in interval notation. Use a comma to separate answers as needed.) A. The function is concave upward on \( \square \). It is never concave downward. B. The function is concave upward on \( \square \). It is concave downward on \( \square . ~ \) C. The function is concave downward on \( \square \). It is never concave upward. Find the location of any inflection points of \( f(x) \). Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. There is an inflection point at \( x=\square \). (Type an integer or a decimal. Use a comma to separate answers as needed.) B. There are no inflection points.

Ask by Schofield Ayala. in the United States
Mar 18,2025

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The function \( f(x) = 1 + 3e^{-0.2x} \) is concave upward on \((-\infty, \infty)\) and has no inflection points.

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To summarize the pertinent information for the function \( f(x) = 1 + 3 e^{-0.2 x} \), we first note that it is an exponential function that starts at \( f(0) = 4 \) and approaches 1 as \( x \) increases. The graph will be a decreasing curve that approaches its horizontal asymptote at \( y = 1 \) as \( x \) goes to infinity. For concavity, we find the second derivative, which tells us about the curvature of the function. The function \( f(x) \) is concave upward for all \( x \) greater than 0 and does not exhibit concave downward intervals. So the correct choice is A: The function is concave upward on \( (0, \infty) \). It is never concave downward. As for inflection points, since \( f(x) \) shows no changes in concavity within its domain, we conclude that there are no inflection points. Therefore, the correct choice is B: There are no inflection points.

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