Construct a circle of radius 5 cm . Then construct a pair of tangents to the circle such that the angle between them is \( 60^{\circ} \).
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Extra Insights
To create tangents that are \( 60^{\circ} \) apart from a circle of radius 5 cm, start by drawing the circle centered at point O. From the center O, draw a radius OA. Since you want the angle between the two tangents to be \( 60^{\circ} \), construct an isosceles triangle OAB, where the lengths OA and OB equal the radius (5 cm), and the angle AOB measures \( 60^{\circ} \). Calculate the distance from the center to the point where the two tangents touch the circle (tangent point P) by using the formula: length of tangents = \( \sqrt{OA^2 - OP^2} = \sqrt{25 - OP^2} \). The longer side ensures the tangents at points T1 and T2 form the desired angle. For an easier visual, you can use a protractor to measure \( 30^{\circ} \) from each radius (since each tangent forms a right angle with the radius at the point of tangency) to mark points T1 and T2 outside the circle. Once you have the points T1 and T2 determined, simply draw straight lines from those points to T1 and T2 to form your tangents. You'll see the beautiful symmetry and elegance come together with that perfect \( 60^{\circ} \) angle!
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