Pregunta
Summarize the pertinend informalion obiained by applying the graptiny stralegy and sketch the graph of
.
Solect the cortect choico beiow and, it necessary, fill in the answer box to completo your choice.
A. The funcion
is decreasing on the subinterval(s)
(Type your answor in interval nctation. Type an exacl answer, us ng radicals as nenfed IJse a comma to separale answers as nceded.)
B. The function I is never docreasing.
Select the correct choice below and, if necessary, fill in the answer box to complele your choice.
A. Tho function
has a local maximum at
.
(Type an exact answeI, using rachads as needed. Uso a comma to separalo answers as needed.)
B. The function I has no focal maximum.
Select the corroct choice below and, if necessary, fill in the answer box to complele your choice.
A. The function
has a local minimum at
(Type an exact answet, using radicals as noeded. Use a comma lo separeto answors as noodod.)
B. The function I has no local minimum,
A. The funcion
(Type your answor in interval nctation. Type an exacl answer, us ng radicals as nenfed IJse a comma to separale answers as nceded.)
B. The function I is never docreasing.
A. Tho function
(Type an exact answeI, using rachads as needed. Uso a comma to separalo answers as needed.)
B. The function I has no focal maximum.
A. The function
(Type an exact answet, using radicals as noeded. Use a comma lo separeto answors as noodod.)
B. The function I has no local minimum,
Ask by Franklin George. in the United States
Mar 11,2025
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
Responder
The function
is decreasing on the intervals
and
. It has local maxima at
and
, and a local minimum at
.
Solución
Consider the function
An equivalent form is
Step 1. Find the Critical Points
Differentiate
:
Factor the derivative:
Setting
gives
Thus, the critical points are:
Step 2. Monotonicity
To determine where
is increasing or decreasing, test the sign of
on the intervals determined by the critical points.
-
Interval
:
Take. Then, Sois increasing. -
Interval
:
Take. Then, Sois decreasing. -
Interval
:
Take. Then, Sois increasing. -
Interval
:
Take. Then, Sois decreasing.
Thus, the function is decreasing on the intervals
Step 3. Local Extrema
-
Local Maxima:
At:
changes from increasing to decreasing.
At:
changes from increasing to decreasing. These are local maxima. -
Local Minimum:
At:
changes from decreasing (for to ) to increasing (for to ). Thus, there is a local minimum at.
Step 4. Summary of Answers
-
Decreasing Intervals:
The functionis decreasing on -
Local Maximum:
The functionhas a local maximum at -
Local Minimum:
The functionhas a local minimum at
Graph Sketch
- The graph is symmetric (even function) because
. - It increases on
then decreases on , has a local minimum at , increases on , and finally decreases on . - The local maxima occur at
and ; the local minimum occurs at .
Final Answers
-
Choice for the decreasing intervals:
A. The functionis decreasing on . -
Choice for the local maximum:
A. The functionhas a local maximum at . -
Choice for the local minimum:
A. The functionhas a local minimum at .
Respondido por UpStudy AI y revisado por un tutor profesional
Como
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Mind Expander
To analyze the function
, we can find its first and second derivatives to determine intervals of increase or decrease, as well as local extrema. We discover that
is decreasing in the intervals
and
. So, select A for that statement.
Additionally, upon further investigation, we can conclude that the function indeed has local maximum points at
and
, thus confirming option A for the local maximum. However, the function does not present a local minimum since it doesn’t dip below the behavior of its critical points, leading to selection B for local minimum assertion. Happy graphing!

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