Sarn and Paul started a business. Their investments were in the ratio 6.7 , respectively. How much did Paul invest if Sam's investment was \$828? \( \$ 986 \) \( \$ 844 \) \( \$ 894 \) \( \$ 710 \)

To find how much Paul invested, we first need to understand the ratio of their investments. If Sarn's investment is \(6x\) and Paul's investment is \(7x\), and we know Sarn's investment is \$828, we can set up the equation: \(6x = 828\) Now, solving for \(x\): \(x = 828 / 6 = 138\) Now, we can find Paul's investment using \(7x\): \(7x = 7 \times 138 = 966\) Looks like we've made a calculation error. Let's try calculating it again from the ratio: If Sarn's investment is represented as \(6\) parts, and Paul's as \(7\) parts, the total is \(6 + 7 = 13\) parts. We know Sarn's investment of \(6\) parts equals \$828. To find the value of one part, we divide: \(1\) part = \(828 / 6 = 138\) Now we can calculate Paul's investment: Paul's investment, which is \(7\) parts = \(7 \times 138 = 966\) After re-evaluating the calculations, it appears that there was an inconsistency as well with the options. As previously noted, Paul's investment should be \(966\). Thus, based on the options provided and the calculations done so far, the answer must be reviewed, or perhaps there was an intended error in the financial portions extracted. If we categorize this correctly with ratios, the solution may reroute some calculations to achieve accuracy, not the capital formats. Always remember to validate the ratios accurately to ascertain best projections in investments!