Pregunta
upstudy study bank question image url

Answer the following questions for the price-demand equation. \( p+0.002 \mathrm{x}=50 \) (A) Express the demand x as a function of the price p . \( \mathrm{x}=\square \) The domain of this function is (Type an inequality or a compound inequality.) (B) Find the elasticity of demand, \( \mathrm{E}(\mathrm{p}) \). \( \mathrm{E}(\mathrm{p})=\square \) (C) What is the elasticity of demand when \( \mathrm{p}=\mathbf{2 5} \) ? The elasticity of demand when \( \mathrm{p}=25 \) is \( \square \) (Type an integer or a simplified fraction.)

Ask by Wyatt Hobbs. in the United States
Mar 03,2025

Solución de inteligencia artificial de Upstudy

Respuesta verificada por el tutor

Responder

(A) \( x = 500(50 - p) \) Domain: \( 0 \leq p \leq 50 \) (B) \( E(p) = -\frac{p}{50 - p} \) (C) When \( p = 25 \), the elasticity is \( -1 \).

Solución

We start with the price-demand equation:   p + 0.002·x = 50 (A) Solve for the demand x as a function of p.   Subtract p from both sides:    0.002·x = 50 – p   Then divide by 0.002:    x = (50 – p) / 0.002   Since 1/0.002 = 500, we can write:    x = 500·(50 – p)   Domain: Because x represents a demand (which must be nonnegative) and p represents a price (usually nonnegative), we require:    500·(50 – p) ≥ 0 ⟹ 50 – p ≥ 0 ⟹ p ≤ 50   Also, p should be nonnegative, so p ≥ 0.   Thus, the domain is:    0 ≤ p ≤ 50 (B) Find the elasticity of demand, E(p).   Recall the formula for the elasticity of demand:    E(p) = (p/x) · (dx/dp)   First, differentiate x = 500·(50 – p) with respect to p:    dx/dp = 500·(–1) = –500   Now substitute x and dx/dp into the elasticity formula:    E(p) = (p / (500·(50 – p))) · (–500) = –p/(50–p) (C) Determine the elasticity when p = 25.   Substitute p = 25 into E(p):    E(25) = –25 / (50 – 25) = –25/25 = –1 In summary:   (A) x = 500(50 – p)  with domain 0 ≤ p ≤ 50   (B) E(p) = –p/(50 – p)   (C) When p = 25, the elasticity is –1.

Respondido por UpStudy AI y revisado por un tutor profesional

error msg
Explicar
Simplifique esta solución

Bonus Knowledge

To solve for the price-demand equation \( p + 0.002x = 50 \): (A) Rearranging the equation to express demand \( x \) as a function of price \( p \): First, isolate \( x \): \[ 0.002x = 50 - p \] Now, divide by \( 0.002 \): \[ x = \frac{50 - p}{0.002} \] So, the demand function is: \[ \mathrm{x} = 25000 - 500p \] The domain of this function is governed by the values \( p \) can take while keeping \( x \) non-negative: \[ 50 - p \geq 0 \] This implies the inequality: \[ p \leq 50 \] (B) To find the elasticity of demand \( E(p) \), we use the formula: \[ E(p) = \frac{dx/dp \cdot p}{x} \] From the demand function \( x = 25000 - 500p \), we differentiate with respect to \( p \): \[ \frac{dx}{dp} = -500 \] Now we substitute \( x \) and \( \frac{dx}{dp} \): \[ E(p) = \frac{-500 \cdot p}{25000 - 500p} \] (C) Now we calculate the elasticity of demand when \( p = 25 \): Substituting \( p = 25 \) into the \( x \) function: \[ x = 25000 - 500(25) = 25000 - 12500 = 12500 \] Now substituting \( p = 25 \) and \( x = 12500 \) into the elasticity formula: \[ E(25) = \frac{-500 \cdot 25}{12500} \] Calculating \( E(25) \): \[ E(25) = \frac{-12500}{12500} = -1 \] So, the answers are: (A) \( \mathrm{x} = 25000 - 500p \); Domain: \( p \leq 50 \) (B) \( \mathrm{E}(\mathrm{p}) = \frac{-500p}{25000 - 500p} \) (C) The elasticity of demand when \( \mathrm{p} = 25 \) is \( -1 \)

preguntas relacionadas

Latest Economics Questions

¡Prueba Premium ahora!
¡Prueba Premium y hazle a Thoth AI preguntas de matemáticas ilimitadas ahora!
Quizas mas tarde Hazte Premium
Estudiar puede ser una verdadera lucha
¿Por qué no estudiarlo en UpStudy?
Seleccione su plan a continuación
Prima

Puedes disfrutar

Empieza ahora
  • Explicaciones paso a paso
  • Tutores expertos en vivo 24/7
  • Número ilimitado de preguntas
  • Sin interrupciones
  • Acceso completo a Respuesta y Solución
  • Acceso completo al chat de PDF, al chat de UpStudy y al chat de navegación
Básico

Totalmente gratis pero limitado

  • Solución limitada
Bienvenido a ¡Estudia ahora!
Inicie sesión para continuar con el recorrido de Thoth AI Chat
Continuar con correo electrónico
O continuar con
Al hacer clic en "Iniciar sesión", acepta nuestros términos y condiciones. Términos de Uso & Política de privacidad