Find the $$ x $$ and $$ y $$ intercepts of this linear equation. $$ \begin{array}{l}5 x+3 y=15 \ x \text {-intercept }(3,[?])\end{array} $$

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1. **Finding the $$ x $$-intercept:**

To find the $$ x $$-intercept, set $$ y=0 $$ in the equation:
   $$
   5x + 3(0) = 15 \quad \Rightarrow \quad 5x = 15.
   $$
   Solve for $$ x $$:
   $$
   x = \frac{15}{5} = 3.
   $$
   Therefore, the $$ x $$-intercept is $$(3, 0)$$.

2. **Finding the $$ y $$-intercept:**

To find the $$ y $$-intercept, set $$ x=0 $$ in the equation:
   $$
   5(0) + 3y = 15 \quad \Rightarrow \quad 3y = 15.
   $$
   Solve for $$ y $$:
   $$
   y = \frac{15}{3} = 5.
   $$
   Therefore, the $$ y $$-intercept is $$(0, 5)$$.
The $$ x $$-intercept is $$(3, 0)$$ and the $$ y $$-intercept is $$(0, 5)$$.

Find the and intercepts
of this linear equation.

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Find the and intercepts of this linear equation.