Pregunta
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The following data set is the age of customers at the ice cream shop: \[ 18,52,42,36,5,31,29,22 \] Find the median.

Ask by Johnson Zimmerman. in the United States
Mar 09,2025

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The median age is 30.

Solución

1. **Order the data from least to greatest:** The ordered data set is: \[ 5,\, 18,\, 22,\, 29,\, 31,\, 36,\, 42,\, 52 \] 2. **Determine the number of observations:** There are \(8\) data points. 3. **Identify the middle two values:** Since the number of observations is even, the median is the average of the \(\frac{n}{2}\)-th and the \(\left(\frac{n}{2}+1\right)\)-th terms. - The \(4\)-th term is \(29\). - The \(5\)-th term is \(31\). 4. **Calculate the median:** \[ \text{Median} = \frac{29 + 31}{2} = \frac{60}{2} = 30 \] The median is \(30\).

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Beyond the Answer

To find the median, first, you need to sort the ages in ascending order: \[ 5, 18, 22, 29, 31, 36, 42, 52 \] Since there are 8 numbers (an even count), the median will be the average of the two middle values. The middle values are 29 and 31. So, the median is: \[ \frac{29 + 31}{2} = \frac{60}{2} = 30 \] Thus, the median age of customers at the ice cream shop is 30.

preguntas relacionadas

Question 12(Mulliple Choice Warth 5 points) \[ (04.06 \mathrm{HC}) \] A researcher wants to test the claim that the proportion of juniors who watch television regularly is greater than the proportion of seniors who watch television regularly She finds that 56 of 70 randomly selected juniors and 47 of 85 randomly selected seniors report watching television regularly. Construct \( 95 \% \) confidence intervals for each population proportion. Which of the statemente gives the correct outcome of the research or's tert of the dalim? The \( 95 \% \) confidence interval for juniors is (706, 894), and the \( 95 \% \) confidence interval for seniors is ( 447,659 ). Since the intervals overlap, there is not enough evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is (721, 879), and the \( 95 \% \) confidence interval for seniors is (464, 642). Since the interval for juniors is higher than the interval for seniors, there is evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is ( 706,894 ), and the \( 95 \% \) confidence interval for seniors is ( 447,659 ). Since the interval for juniors is higher than the interval for seniors, there is evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is ( \( 721, .879 \) ), and the \( 95 \% \) confidence interval for seniors is (464, 642). Since the intervals overlap, there is not enough evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors.

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