Kyle and Ryan take entrance exams at two different universities.
Kyle scores a 439 on an exam with a mean of 360 and a standard deviation of 59 .
Kyle’s corresponding z-score is
Round your answer to two decimal places, if needed.
Ryan scores a 41 on an exam with a mean of 25 and a standard deviation of 5.5 .
Ryan’s corresponding z-score is
Round your answer to two decimal places, if needed.
If acceptance is based on the entrance exam alone, who do you think is more likely to be accepted at
Kyle
Ryan

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UpStudy AI · Accepted Answer

Kyle's z-score is calculated using the formula  
$$
z = \frac{x - \mu}{\sigma}
$$

For Kyle:  
$$
z = \frac{439 - 360}{59} = \frac{79}{59} \approx 1.34
$$

Ryan's z-score is calculated similarly:  
$$
z = \frac{41 - 25}{5.5} = \frac{16}{5.5} \approx 2.91
$$

Since a higher z-score indicates a performance further above the mean, Ryan's z-score of approximately $$2.91$$ is higher than Kyle's z-score of approximately $$1.34$$. Therefore, based solely on the entrance exam scores, Ryan is more likely to be accepted.
Kyle's z-score is 1.34 and Ryan's z-score is 2.91. Ryan is more likely to be accepted.

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