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To construct quadrilateral \( ABCD \) with sides \( BC = 3 \, \text{cm} \), \( AD = 6 \, \text{cm} \), \( AC = 4 \, \text{cm} \), and \( BD = 7 \, \text{cm} \), follow these steps:
1. Draw segment \( BC \) of \( 3 \, \text{cm} \).
2. From point \( B \), draw a circle with radius \( 6 \, \text{cm} \).
3. From point \( C \), draw a circle with radius \( 4 \, \text{cm} \).
4. The intersection of these circles is point \( A \).
5. From point \( B \), draw a circle with radius \( 7 \, \text{cm} \).
6. From point \( A \), draw a circle with radius \( 6 \, \text{cm} \).
7. The intersection of these circles is point \( D \).
8. Connect points \( A \), \( B \), \( C \), and \( D \) to form quadrilateral \( ABCD \).
This construction ensures all given side lengths are satisfied.
Solución
To construct the quadrilateral \( ABCD \) with the given side lengths, we can follow these steps:
1. **Draw Segment \( BC \)**:
- Start by drawing a line segment \( BC \) that is \( 3 \, \text{cm} \) long.
2. **Draw Circle for Point \( A \)**:
- From point \( B \), draw a circle with a radius of \( 6 \, \text{cm} \) (since \( AD = 6 \, \text{cm} \)).
- From point \( C \), draw another circle with a radius of \( 4 \, \text{cm} \) (since \( AC = 4 \, \text{cm} \)).
- The intersection of these two circles will give you point \( A \).
3. **Draw Circle for Point \( D \)**:
- From point \( B \), draw a circle with a radius of \( 7 \, \text{cm} \) (since \( BD = 7 \, \text{cm} \)).
- From point \( A \), draw a circle with a radius of \( 6 \, \text{cm} \) (since \( AD = 6 \, \text{cm} \)).
- The intersection of these two circles will give you point \( D \).
4. **Connect the Points**:
- Finally, connect points \( A \), \( B \), \( C \), and \( D \) to form the quadrilateral \( ABCD \).
This construction ensures that all the given lengths are satisfied. The quadrilateral \( ABCD \) will have the sides \( AB \), \( BC \), \( CD \), and \( DA \) with the specified lengths.
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