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Solve the quadratic equation using completing the square. \( t^{2}=10 t+19 \)

Ask by Clark Marsh. in the United States
Mar 01,2025

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The solutions are \( t = 5 + 2\sqrt{11} \) and \( t = 5 - 2\sqrt{11} \).

Solución

We are given the quadratic equation   t² = 10t + 19. Step 1. First, bring all terms to one side by subtracting 10t + 19 from both sides:   t² - 10t - 19 = 0. Step 2. Isolate the constant term:   t² - 10t = 19. Step 3. To complete the square, take the coefficient of t, which is -10, divide it by 2, and then square it.   Half of -10 is -5, and (-5)² = 25. Add 25 to both sides of the equation:   t² - 10t + 25 = 19 + 25. Step 4. Now the left-hand side is a perfect square:   (t - 5)² = 44. Step 5. Taking the square root of both sides yields:   t - 5 = ±√44. Step 6. Simplify √44. Since 44 = 4 × 11, we have:   √44 = √(4×11) = 2√11. So, the equation becomes:   t - 5 = ±2√11. Step 7. Finally, solve for t by adding 5 to both sides:   t = 5 ± 2√11. Thus, the solutions to the quadratic equation using completing the square are:   t = 5 + 2√11  and  t = 5 - 2√11.

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To solve the equation \( t^{2} = 10t + 19 \) by completing the square, we first rewrite it in standard form: \[ t^{2} - 10t - 19 = 0 \] Next, we complete the square for the quadratic term. We'll move the constant to the other side: \[ t^{2} - 10t = 19 \] To complete the square, take half of the coefficient of \( t \) (which is -10), square it, and add it to both sides. Half of -10 is -5, and squaring it gives us 25: \[ t^{2} - 10t + 25 = 19 + 25 \] This simplifies to: \[ (t - 5)^{2} = 44 \] Now, take the square root of both sides: \[ t - 5 = \pm \sqrt{44} \] Since \( \sqrt{44} = 2\sqrt{11} \), we have: \[ t - 5 = \pm 2\sqrt{11} \] Finally, solving for \( t \): \[ t = 5 \pm 2\sqrt{11} \] Thus, the solutions are: \[ t = 5 + 2\sqrt{11} \quad \text{and} \quad t = 5 - 2\sqrt{11} \]

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