Part: \( 2 / 5 \) Part 3 of 5 Calculate the Pearson's index of skewness. (Round the mean, median and standard deviation to one decimal place and Pearson's index to two decimal places.) It can be conduded that the distribution is not significantly \( \mathbf{T} \), skewed. Skip Part Recheck Try again Save For Later Sut

1. Write the formula for Pearson's index of skewness: \[ \text{Pearson's Skewness} = \frac{3(\bar{x} - M)}{s} \] where \(\bar{x}\) is the mean, \(M\) is the median, and \(s\) is the standard deviation. 2. Insert the given (or previously calculated) values, rounded to one decimal place. For example, if \[ \bar{x} = 20.4,\quad M = 20.0,\quad s = 4.5, \] then substitute these into the formula. 3. Compute the difference between the mean and the median: \[ \bar{x} - M = 20.4 - 20.0 = 0.4. \] 4. Multiply the difference by 3: \[ 3(\bar{x} - M) = 3 \times 0.4 = 1.2. \] 5. Divide by the standard deviation: \[ \text{Pearson's Skewness} = \frac{1.2}{4.5} \approx 0.27. \] 6. Round the final result to two decimal places (in this example, it is already \(0.27\)). 7. Interpret the result. Since the Pearson’s index of skewness is close to 0 (in this case, \(0.27\)), it can be concluded that the distribution is not significantly skewed.