A tank on a road roller is filled with water to make the roller heavy. The tank is a cylinder that has a height of 6 feet and a radius of 2 feet. One cubic foot of water weighs 62.5 pounds. Find the weight of the water in the tank. To the nearest whole number, the water weighs \( \square \) pounds.

To find the weight of the water in the tank, we first need to determine the volume of the cylindrical tank using the formula for the volume of a cylinder: \[ \text{Volume} = \pi r^2 h \] Substituting the given values (radius \( r = 2 \) feet and height \( h = 6 \) feet): \[ \text{Volume} = \pi (2^2) (6) = \pi (4) (6) = 24\pi \text{ cubic feet} \] Now, we'll calculate the weight of the water by multiplying the volume by the weight of one cubic foot of water: \[ \text{Weight} = \text{Volume} \times \text{Weight per cubic foot} = 24\pi \times 62.5 \] Approximating \( \pi \) as 3.14, we get: \[ \text{Weight} \approx 24 \times 3.14 \times 62.5 \approx 24 \times 196.25 \approx 4710 \text{ pounds} \] To the nearest whole number, the water weighs approximately **4710 pounds**.