Consider a political discussion group consiting of 5 Democrats, 10 Repiticans, and 6 Independents, Suppose that two croup members are randomly selected, in succescion, to attend a political convention. Find the probability of selecing an Independent and then a Democrat. \( \square \) (Type an integer or a simplified fraction.)

To find the probability of selecting an Independent followed by a Democrat, we start by calculating the total number of group members. There are \(5 + 10 + 6 = 21\) members in total. The probability of selecting an Independent first is \(\frac{6}{21}\). After selecting one Independent, there are now \(20\) members left, and \(5\) Democrats remaining. Thus, the probability of selecting a Democrat second is \(\frac{5}{20}\). Now we multiply these probabilities together: \[ P(\text{Independent then Democrat}) = \frac{6}{21} \times \frac{5}{20} = \frac{30}{420} = \frac{1}{14} \] So, the probability of selecting an Independent and then a Democrat is \(\frac{1}{14}\).