\( \frac { ( 3 b ) ^ { 2 } + 12 a b ^ { 5 } } { 3 b } = \square b + \square a b \)

To simplify the expression \( \frac { ( 3 b ) ^ { 2 } + 12 a b ^ { 5 } } { 3 b } \), we first simplify the numerator. The term \( (3b)^2 \) equals \( 9b^2 \), and the entire numerator becomes \( 9b^2 + 12ab^5 \). Now, we can divide each term by \( 3b \): 1. \( \frac{9b^2}{3b} = 3b \) 2. \( \frac{12ab^5}{3b} = 4ab^4 \) So the full simplification gives us \( 3b + 4ab^4 \). Thus, \( 3b + 4ab^4 \) can be written in the format \( \square b + \square ab \) where \( \square = 3 \) for \( b \) and \( \square = 4a \) for \( ab \). In conclusion, the expression simplifies to: \( 3b + 4ab^4 \).