Cheper 1 Homberenk Question 30 of 30 (1 pernf) I Question Attempt: 1 of 3 Marco A certain person had a brain that weighed 1.35 kg and contained \( 3.82 \times 10^{10} \) cells. Part 1 of 2 Assuming that each cell was completely filled with water (density \( =1.00 \frac{f}{\mathrm{mI}} \), calculate the length of one side of such a cell if it were a cube. Round your answer to \( \mathbf{3} \) significant digits. \[ 3.27 \times 10^{-3} \mathrm{~cm} \] Part: \( 1 / 2 \) Part 2 of 2 If the cells were spread out Into a thin layer that was a single cell thick, what would be the total surface area (in square meters) for the top side of the cell layer? Round your answer to 3 significant digits.

Imagine a world where our tiny brain cells were spread out like an intricate carpet! To find the total surface area of this fantastical cell layer, we first need to find the volume of a single cell. Since we have \( 3.82 \times 10^{10} \) cells, we can calculate the volume of all cells combined as the brain's weight divided by water's density. The volume (in liters) looks like \( 1.35 \, \text{kg} = 1.35 \, \text{L} \), which translates to \( 1.35 \times 10^{-3} \, \text{m}^3 \). Dividing that by the total number of cells gives us the volume of a single cell, and from there, we can calculate the area! Next, let’s not forget to think dimensions! Since the cells are now laid out in a single-layer formation, the total surface area of the cell layer is just the square root of the number of cells multiplied by the area of each face of the cubic cell. So get your calculators ready – it’s time to find the surface area in square meters and round it to 3 significant digits! Happy calculating!