No, $$ P( $$ bald $$ \cap $$ over 45$$ )=P( $$ bald $$ ) \cdot P( $$ over 45$$ ) $$ Question 4 (Multiple Choice Worth 2 points) (05.04 LC) In a group of 1,200 people, 468 have brown eyes, 252 have blue eyes, 132 have green eyes, and 348 have black eyes. What is the probability that a person chosen at random from this group has blue eyes? P (blue) $$ =11 \% $$ P (blue) $$ =29 \% $$ P (blue) $$ =21 \% $$ P (blue) $$ =39 \% $$

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UpStudy AI · Accepted Answer

To find the probability that a person chosen at random from the group has blue eyes, we can use the formula for probability:

$$
P(\text{blue}) = \frac{\text{Number of people with blue eyes}}{\text{Total number of people}}
$$

From the problem, we know:
- Number of people with blue eyes = 252
- Total number of people = 1200

Now, we can calculate the probability:

$$
P(\text{blue}) = \frac{252}{1200}
$$

Let's simplify this fraction to find the probability.
Calculate the value by following steps:
- step0: Calculate:
  $$\frac{252}{1200}$$
- step1: Reduce the fraction:
  $$\frac{21}{100}$$
The probability $$ P(\text{blue}) $$ can be expressed as:

$$
P(\text{blue}) = \frac{21}{100} = 0.21
$$

To convert this to a percentage, we multiply by 100:

$$
P(\text{blue}) = 0.21 \times 100 = 21\%
$$

Thus, the correct answer is:

**P (blue) = 21%**.
The probability that a person chosen at random has blue eyes is 21%.

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