Two dice are thrown. List all the possible results. Find the probability of throwing a total of 6 .

When two dice are thrown, each die can land on any number from 1 to 6, resulting in 6 × 6 = 36 equally likely outcomes. These outcomes can be written as ordered pairs (a, b), where "a" is the number on the first die and "b" is the number on the second die. The complete list of outcomes is: (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6) (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6) (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6) (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6) (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6) (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6) To find the probability of throwing a total of 6, we need to count the number of outcomes where the sum of the two dice equals 6. Let's list those favorable outcomes: • (1, 5) → 1 + 5 = 6 • (2, 4) → 2 + 4 = 6 • (3, 3) → 3 + 3 = 6 • (4, 2) → 4 + 2 = 6 • (5, 1) → 5 + 1 = 6 There are 5 outcomes that produce a total of 6. Since all 36 outcomes are equally likely, the probability P(total of 6) is given by:   P(total of 6) = Number of favorable outcomes / Total outcomes = 5/36 Thus, the probability of throwing a total of 6 with two dice is 5/36.