If $$ f(x) $$ is defined as follows, find (a) $$ f(-1) $$, (b) $$ f(0) $$, and (c) $$ f(1) $$ $$ f(x)=\left\{\begin{array}{ll}x^{2} & ext { if } x0\end{array} ight. $$ (a) $$ f(-1)=1 $$ (Simplify your answer.) (b) $$ f(0)=3 $$ (Simplify your answer.) (c) $$ f(1)=\square $$ (Simplify your answer.)

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If $$ f(x) $$ is defined as follows, find (a) $$ f(-1) $$, (b) $$ f(0) $$, and (c) $$ f(1) $$ $$ f(x)=\left\{\begin{array}{ll}x^{2} & 	ext { if } x<0 \ 3 & 	ext { if } x=0 \ 2 x+1 & 	ext { if } x>0\end{array}ight. $$ (a) $$ f(-1)=1 $$ (Simplify your answer.) (b) $$ f(0)=3 $$ (Simplify your answer.) (c) $$ f(1)=\square $$ (Simplify your answer.)

UpStudy AI · Accepted Answer

We are given the function: f(x) = { x² if x < 0 3 if x = 0 2x + 1 if x > 0 } (a) For f(-1): Since -1 < 0, we use f(x) = x². f(-1) = (-1)² = 1 (b) For f(0): Since x = 0, we use the middle case. f(0) = 3 (c) For f(1): Since 1 > 0, we use f(x) = 2x + 1. f(1) = 2(1) + 1 = 3 Thus, in simplified form: (a) f(-1) = 1 (b) f(0) = 3 (c) f(1) = 3 (a) $$ f(-1) = 1 $$ (b) $$ f(0) = 3 $$ (c) $$ f(1) = 3 $$

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