When she was 9 years of age, a girl did a science fair experiment in which she tested professional touch therapists to see if they could sense her energy field She flipped a coin to select either her right hand or her left hand, and then she asked the therapists to identify the selected hand by placing their hand just under her hand without seeing it and without touching it. Among 280 trials, the touch therapists were correct 123 times. Use a 0.10 significance level to test the claim that touch therapists use a method equivalent to random guesses. Do the results suggest that touch therapists are effective? Let p denote the population proportion of correct hand selections by touch therapists. Identify the null and alternative hypotheses to test the claim that touch therapists use a method equivalent to random guesses. $$ H_{0}: p=0.5 $$ $$ H_{1}: p
eq 0.5 $$ (Type integers or decimals. Do not round) Identify the test statistic. $$ z=\square $$ (Round to two decimal places as needed.)

Question

When she was 9 years of age, a girl did a science fair experiment in which she tested professional touch therapists to see if they could sense her energy field She flipped a coin to select either her right hand or her left hand, and then she asked the therapists to identify the selected hand by placing their hand just under her hand without seeing it and without touching it. Among 280 trials, the touch therapists were correct 123 times. Use a 0.10 significance level to test the claim that touch therapists use a method equivalent to random guesses. Do the results suggest that touch therapists are effective? Let p denote the population proportion of correct hand selections by touch therapists. Identify the null and alternative hypotheses to test the claim that touch therapists use a method equivalent to random guesses. $$ H_{0}: p=0.5 $$ $$ H_{1}: p 
eq 0.5 $$ (Type integers or decimals. Do not round) Identify the test statistic. $$ z=\square $$ (Round to two decimal places as needed.)

UpStudy AI · Accepted Answer

1. Define the sample proportion:
$$
\hat{p}=\frac{123}{280}\approx 0.4393
$$

2. Under the null hypothesis, $$ p=0.5 $$. The standard error is given by:
$$
SE = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.5\cdot0.5}{280}} = \sqrt{\frac{0.25}{280}}
$$
$$
SE \approx \sqrt{0.000892857} \approx 0.02989
$$

3. The test statistic $$ z $$ is computed as:
$$
z = \frac{\hat{p}-0.5}{SE} = \frac{0.4393-0.5}{0.02989} \approx \frac{-0.0607}{0.02989} \approx -2.03
$$

Thus, the test statistic is:
$$
z = -2.03
$$
The test statistic is $$ z = -2.03 $$.

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