5 Homework
The largest tace, contained approximately 1 kg of onion for every 6.8 kg of grilled steak. The total weight of these two ingredients was 617.1 kg . How many kilograms of
each ingredient were used?
In of 40 points
In the taco, approximately of onion and of grilled steak were used.
(Type integers or decimals rounded to the nearest tenth as needed.)

Ask by Maxwell Huff. in the United States

Mar 22,2025

Question

5 Homework
The largest tace, contained approximately 1 kg of onion for every 6.8 kg of grilled steak. The total weight of these two ingredients was 617.1 kg . How many kilograms of
each ingredient were used?
In of 40 points
In the taco, approximately of onion and of grilled steak were used.
(Type integers or decimals rounded to the nearest tenth as needed.)

Ask by Maxwell Huff. in the United States

Mar 22,2025

UpStudy AI · Accepted Answer

1. Let $$ x $$ be the kilogram amount of onion, and since there is 1 kg of onion for every 6.8 kg of grilled steak, the steak weight is $$ 6.8x $$.

2. The total weight equation is:
   $$
   x + 6.8x = 617.1
   $$

3. Combine like terms:
   $$
   7.8x = 617.1
   $$

4. Solve for $$ x $$ by dividing both sides by 7.8:
   $$
   x = \frac{617.1}{7.8} \approx 79.1
   $$
   So, approximately $$ 79.1 $$ kg of onion.

5. Find the steak weight by multiplying $$ x $$ by 6.8:
   $$
   6.8x \approx 6.8 \times 79.1 \approx 538.0
   $$
   So, approximately $$ 538.0 $$ kg of grilled steak.

6. Therefore, the taco contained approximately $$ 79.1 $$ kg of onion and $$ 538.0 $$ kg of grilled steak.
The taco contained approximately 79.1 kg of onion and 538.0 kg of grilled steak.

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