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1. Circle true or false for each statement. \( \begin{array}{l}\text { a. true / false A perfect square may be negative. } \\ \begin{array}{l}\text { b. true / false } \\ \text { c. true / false perfect cube may be negative. } \\ \text { d. true / false }\end{array}\end{array} \begin{array}{l}\text { The square root of a negative number does not exist. }\end{array} \)

Ask by Graham Peterson. in the United States
Mar 22,2025

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**a.** False **c.** True **d.** True

Solución

**a.** False - For any real number \( n \), the square \( n^2 \) is nonnegative. Therefore, a perfect square (which is of the form \( n^2 \)) cannot be negative. **c.** True - The cube of a number can be negative. For example, if \( n = -2 \), then \( n^3 = -8 \), which is negative. Thus, a perfect cube (of the form \( n^3 \)) may be negative. **d.** True - In the context of real numbers, the square root of a negative number is not defined because there is no real number \( n \) such that \( n^2 \) is negative. (Note: In the complex number system, we define \( \sqrt{-1} = i \), but the statement is typically considered within the real number system.)

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Bonus Knowledge

A perfect square is defined as a number that can be expressed as the square of an integer. Since squaring any real number (positive or negative) results in a non-negative number, it's impossible for a perfect square to be negative. Therefore, statement (a) is false. When it comes to perfect cubes, any integer can be cubed, and this includes negative numbers. For example, \((-2)^3 = -8\). Thus, a perfect cube can indeed be negative, making statement (c) true. As for the square root of a negative number, in the realm of real numbers, it does not exist; however, in the field of complex numbers, it can be expressed using 'i' (the imaginary unit). Hence, the statement is true if considering only real numbers.

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