Use reciprocal tables to evaluate to 2 decimal places \( \frac{10}{0.625}+\frac{4}{1.5} \)

To evaluate \( \frac{10}{0.625} + \frac{4}{1.5} \) using reciprocal tables, we first find the reciprocals of the denominators. The reciprocal of \( 0.625 \) is \( 1.6 \) (since \( 0.625 = \frac{5}{8} \), and its reciprocal is \( \frac{8}{5} \)). Therefore, \( \frac{10}{0.625} = 10 \times 1.6 = 16.0 \). Next, the reciprocal of \( 1.5 \) is \( \frac{2}{3} \) or approximately \( 0.6667 \). Thus, \( \frac{4}{1.5} = 4 \times \frac{2}{3} = \frac{8}{3} \), which is approximately \( 2.67 \). Now, adding these two results gives: \( 16.0 + 2.67 = 18.67\). So, to two decimal places, the final answer is \( 18.67 \).