\( \begin{array}{l}\text { Solve the equation. } \\ 5 v^{2}-26 v=24\end{array} \left\lvert\, \begin{array}{l}\text { The solution set is }\{ \} \\ \text { (Type an integer or a simplified } \\ \text { fraction. Use a comma to } \\ \text { separate answers as needed.) }\end{array}\right. \)

**Step 1.** Write the equation in standard form: \[ 5v^2 - 26v = 24 \quad \Rightarrow \quad 5v^2 - 26v - 24 = 0 \] **Step 2.** Identify the coefficients: \[ a = 5, \quad b = -26, \quad c = -24 \] **Step 3.** Use the quadratic formula: \[ v = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] **Step 4.** Compute the discriminant: \[ b^2 - 4ac = (-26)^2 - 4(5)(-24) = 676 + 480 = 1156 \] \[ \sqrt{1156} = 34 \] **Step 5.** Substitute the values into the quadratic formula: \[ v = \frac{-(-26) \pm 34}{2 \cdot 5} = \frac{26 \pm 34}{10} \] **Step 6.** Find the two solutions: \[ v = \frac{26 + 34}{10} = \frac{60}{10} = 6 \] \[ v = \frac{26 - 34}{10} = \frac{-8}{10} = -\frac{4}{5} \] **Step 7.** Write the solution set: \[ \{6, -\frac{4}{5}\} \]