3 What are the $$ 3 r d, 5 $$ th \& 7 th terms of the sequence? $$ f(2)=21, f(n)=f(n-1) \frac{1}{2} $$

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To find the $$3^{rd}$$, $$5^{th}$$, and $$7^{th}$$ terms of the sequence defined by $$f(2) = 21$$ and the recursive relation $$f(n) = f(n-1) \cdot \frac{1}{2}$$, we can calculate the terms step by step.

1. **Calculate $$f(3)$$**:
   $$
   f(3) = f(2) \cdot \frac{1}{2} = 21 \cdot \frac{1}{2} = 10.5
   $$

2. **Calculate $$f(4)$$**:
   $$
   f(4) = f(3) \cdot \frac{1}{2} = 10.5 \cdot \frac{1}{2} = 5.25
   $$

3. **Calculate $$f(5)$$**:
   $$
   f(5) = f(4) \cdot \frac{1}{2} = 5.25 \cdot \frac{1}{2} = 2.625
   $$

4. **Calculate $$f(6)$$**:
   $$
   f(6) = f(5) \cdot \frac{1}{2} = 2.625 \cdot \frac{1}{2} = 1.3125
   $$

5. **Calculate $$f(7)$$**:
   $$
   f(7) = f(6) \cdot \frac{1}{2} = 1.3125 \cdot \frac{1}{2} = 0.65625
   $$

Now we can summarize the results:

- $$f(3) = 10.5$$
- $$f(5) = 2.625$$
- $$f(7) = 0.65625$$

Thus, the $$3^{rd}$$, $$5^{th}$$, and $$7^{th}$$ terms of the sequence are $$10.5$$, $$2.625$$, and $$0.65625$$ respectively.
The 3rd, 5th, and 7th terms of the sequence are 10.5, 2.625, and 0.65625 respectively.

3 What are the th & 7 th
terms of the sequence?

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3 What are the th & 7 th terms of the sequence?