Evaluate the piecewise function at the given values of the independent variable. $$ h(x)=\left\{\begin{array}{ll}\frac{x^{2}-4}{x-2} & ext { if } x
eq 2 \ 7 & ext { if } x=2\end{array} ight. $$ $$ \begin{array}{lll} ext { (a) } h(3) & ext { (b) } h(0) & ext { (c) } h(2)\end{array} $$ $$ \begin{array}{ll} ext { (a) } h(3)=\square\end{array} $$

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Evaluate the piecewise function at the given values of the independent variable. $$ h(x)=\left\{\begin{array}{ll}\frac{x^{2}-4}{x-2} & 	ext { if } x 
eq 2 \ 7 & 	ext { if } x=2\end{array}ight. $$ $$ \begin{array}{lll}	ext { (a) } h(3) & 	ext { (b) } h(0) & 	ext { (c) } h(2)\end{array} $$ $$ \begin{array}{ll}	ext { (a) } h(3)=\square\end{array} $$

UpStudy AI · Accepted Answer

To evaluate $$ h(3) $$, we note that since $$ 3 \neq 2 $$, we use the first piece of the function:
$$
h(x)=\frac{x^2-4}{x-2}.
$$

Substitute $$ x=3 $$ into the expression:
$$
h(3)=\frac{3^2-4}{3-2}=\frac{9-4}{1}=\frac{5}{1}=5.
$$

Thus, 
$$ h(3)=5 $$.
$$ h(3) = 5 $$

Evaluate the piecewise function at the given values of the independent variable.

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