A dog, Bowser, and a cat, Mouser, live in the same house. Their kibble (dry pet food) has the same size pieces. Bowser is fed 120 pieces of kibble at a time and eats at the rate of 20 pieces of kibble in 20 seconds. Mouser is fed 40 pieces of kibble at a time and eats at the rate of 2 pieces of kibble in 20 seconds. If both pets start to eat at 6:30:00 a.m., at what time does Bowser finish his kibble and start to 'help' Mouser eat his kibble?
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Let's start by calculating the eating times for both Bowser and Mouser. Bowser is fed 120 pieces and eats at a rate of 20 pieces in 20 seconds. This translates to 1 piece every second. Therefore, Bowser will take 120 seconds to finish his kibble: 120 pieces × 1 second/piece = 120 seconds (or 2 minutes). So, Bowser finishes his kibble at 6:32:00 a.m. Now for Mouser, who is fed 40 pieces and eats 2 pieces in 20 seconds. That's 1 piece every 10 seconds. Thus, Mouser will take 400 seconds to finish: 40 pieces × 10 seconds/piece = 400 seconds (or 6 minutes and 40 seconds). Starting at 6:30:00 a.m., Mouser finishes at: 6:30:00 a.m. + 6 minutes and 40 seconds = 6:36:40 a.m. After Bowser finishes at 6:32:00 a.m., he would start 'helping' Mouser eat his kibble, which would be at: 6:32:00 a.m.